COORDINATE GEOMETRY | O LEVELS (4024) & IGCSE (0580) | 2025 | Sir Arshad

Exam Prep
Year2026
Duration33m

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jameskofyJul 3, 2026

๐Ÿฏ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ ๐—ด๐—ฒ๐—ผ๐—บ๐—ฒ๐˜๐—ฟ๐˜† ๐Ÿฏ.๐Ÿญ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Use and interpret Cartesian coordinates in twoย dimensions. ๐Ÿฏ.๐Ÿฎ ๐——๐—ฟ๐—ฎ๐˜„๐—ถ๐—ป๐—ด ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Draw straight-line graphs for Examples include: linear equations. โ€ข y = โ€“2x + 5 โ€ข y = 7 โ€“ 4x โ€ข 3x + 2y = 5 ๐Ÿฏ.๐Ÿฏ ๐—š๐—ฟ๐—ฎ๐—ฑ๐—ถ๐—ฒ๐—ป๐˜ ๐—ผ๐—ณ ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Find the gradient of a straight line. 2) Calculate the gradient of a straight line from the coordinates of two points on it. ๐Ÿฏ.๐Ÿฐ ๐—Ÿ๐—ฒ๐—ป๐—ด๐˜๐—ต ๐—ฎ๐—ป๐—ฑ ๐—บ๐—ถ๐—ฑ๐—ฝ๐—ผ๐—ถ๐—ป๐˜ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Calculate the length of a line segment. 2) Find the coordinates of the midpoint of a line segment. ๐Ÿฏ.๐Ÿฑ ๐—˜๐—พ๐˜‚๐—ฎ๐˜๐—ถ๐—ผ๐—ป๐˜€

Assane HDJul 3, 2026

๐Ÿฏ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ ๐—ด๐—ฒ๐—ผ๐—บ๐—ฒ๐˜๐—ฟ๐˜† ๐Ÿฏ.๐Ÿญ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Use and interpret Cartesian coordinates in twoย dimensions. ๐Ÿฏ.๐Ÿฎ ๐——๐—ฟ๐—ฎ๐˜„๐—ถ๐—ป๐—ด ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Draw straight-line graphs for Examples include: linear equations. โ€ข y = โ€“2x + 5 โ€ข y = 7 โ€“ 4x โ€ข 3x + 2y = 5 ๐Ÿฏ.๐Ÿฏ ๐—š๐—ฟ๐—ฎ๐—ฑ๐—ถ๐—ฒ๐—ป๐˜ ๐—ผ๐—ณ ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Find the gradient of a straight line. 2) Calculate the gradient of a straight line from the coordinates of two points on it. ๐Ÿฏ.๐Ÿฐ ๐—Ÿ๐—ฒ๐—ป๐—ด๐˜๐—ต ๐—ฎ๐—ป๐—ฑ ๐—บ๐—ถ๐—ฑ๐—ฝ๐—ผ๐—ถ๐—ป๐˜ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Calculate the length of a line segment. 2) Find the coordinates of the midpoint of a line segment. ๐Ÿฏ.๐Ÿฑ ๐—˜๐—พ๐˜‚๐—ฎ๐˜๐—ถ๐—ผ๐—ป๐˜€

JackieJul 3, 2026

๐Ÿฏ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ ๐—ด๐—ฒ๐—ผ๐—บ๐—ฒ๐˜๐—ฟ๐˜† ๐Ÿฏ.๐Ÿญ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Use and interpret Cartesian coordinates in twoย dimensions. ๐Ÿฏ.๐Ÿฎ ๐——๐—ฟ๐—ฎ๐˜„๐—ถ๐—ป๐—ด ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Draw straight-line graphs for Examples include: linear equations. โ€ข y = โ€“2x + 5 โ€ข y = 7 โ€“ 4x โ€ข 3x + 2y = 5 ๐Ÿฏ.๐Ÿฏ ๐—š๐—ฟ๐—ฎ๐—ฑ๐—ถ๐—ฒ๐—ป๐˜ ๐—ผ๐—ณ ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Find the gradient of a straight line. 2) Calculate the gradient of a straight line from the coordinates of two points on it. ๐Ÿฏ.๐Ÿฐ ๐—Ÿ๐—ฒ๐—ป๐—ด๐˜๐—ต ๐—ฎ๐—ป๐—ฑ ๐—บ๐—ถ๐—ฑ๐—ฝ๐—ผ๐—ถ๐—ป๐˜ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Calculate the length of a line segment. 2) Find the coordinates of the midpoint of a line segment. ๐Ÿฏ.๐Ÿฑ ๐—˜๐—พ๐˜‚๐—ฎ๐˜๐—ถ๐—ผ๐—ป๐˜€

Marwan YounisJul 3, 2026

๐Ÿฏ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ ๐—ด๐—ฒ๐—ผ๐—บ๐—ฒ๐˜๐—ฟ๐˜† ๐Ÿฏ.๐Ÿญ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Use and interpret Cartesian coordinates in twoย dimensions. ๐Ÿฏ.๐Ÿฎ ๐——๐—ฟ๐—ฎ๐˜„๐—ถ๐—ป๐—ด ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Draw straight-line graphs for Examples include: linear equations. โ€ข y = โ€“2x + 5 โ€ข y = 7 โ€“ 4x โ€ข 3x + 2y = 5 ๐Ÿฏ.๐Ÿฏ ๐—š๐—ฟ๐—ฎ๐—ฑ๐—ถ๐—ฒ๐—ป๐˜ ๐—ผ๐—ณ ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Find the gradient of a straight line. 2) Calculate the gradient of a straight line from the coordinates of two points on it. ๐Ÿฏ.๐Ÿฐ ๐—Ÿ๐—ฒ๐—ป๐—ด๐˜๐—ต ๐—ฎ๐—ป๐—ฑ ๐—บ๐—ถ๐—ฑ๐—ฝ๐—ผ๐—ถ๐—ป๐˜ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Calculate the length of a line segment. 2) Find the coordinates of the midpoint of a line segment. ๐Ÿฏ.๐Ÿฑ ๐—˜๐—พ๐˜‚๐—ฎ๐˜๐—ถ๐—ผ๐—ป๐˜€

Badeg99Jul 3, 2026

๐Ÿฏ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ ๐—ด๐—ฒ๐—ผ๐—บ๐—ฒ๐˜๐—ฟ๐˜† ๐Ÿฏ.๐Ÿญ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Use and interpret Cartesian coordinates in two dimensions. ๐Ÿฏ.๐Ÿฎ ๐——๐—ฟ๐—ฎ๐˜„๐—ถ๐—ป๐—ด ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Draw straight-line graphs for Examples include: linear equations. โ€ข y = โ€“2x + 5 โ€ข y = 7 โ€“ 4x โ€ข 3x + 2y = 5 ๐Ÿฏ.๐Ÿฏ ๐—š๐—ฟ๐—ฎ๐—ฑ๐—ถ๐—ฒ๐—ป๐˜ ๐—ผ๐—ณ ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Find the gradient of a straight line. 2) Calculate the gradient of a straight line from the coordinates of two points on it. ๐Ÿฏ.๐Ÿฐ ๐—Ÿ๐—ฒ๐—ป๐—ด๐˜๐—ต ๐—ฎ๐—ป๐—ฑ ๐—บ๐—ถ๐—ฑ๐—ฝ๐—ผ๐—ถ๐—ป๐˜ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Calculate the length of a line segment. 2) Find the coordinates of the midpoint of a line segment. ๐Ÿฏ.๐Ÿฑ ๐—˜๐—พ๐˜‚๐—ฎ๐˜๐—ถ๐—ผ๐—ป๐˜€

Solanki RidhinJul 3, 2026

๐Ÿฏ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ ๐—ด๐—ฒ๐—ผ๐—บ๐—ฒ๐˜๐—ฟ๐˜† ๐Ÿฏ.๐Ÿญ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Use and interpret Cartesian coordinates in two dimensions. ๐Ÿฏ.๐Ÿฎ ๐——๐—ฟ๐—ฎ๐˜„๐—ถ๐—ป๐—ด ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Draw straight-line graphs for Examples include: linear equations. โ€ข y = โ€“2x + 5 โ€ข y = 7 โ€“ 4x โ€ข 3x + 2y = 5 ๐Ÿฏ.๐Ÿฏ ๐—š๐—ฟ๐—ฎ๐—ฑ๐—ถ๐—ฒ๐—ป๐˜ ๐—ผ๐—ณ ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Find the gradient of a straight line. 2) Calculate the gradient of a straight line from the coordinates of two points on it. ๐Ÿฏ.๐Ÿฐ ๐—Ÿ๐—ฒ๐—ป๐—ด๐˜๐—ต ๐—ฎ๐—ป๐—ฑ ๐—บ๐—ถ๐—ฑ๐—ฝ๐—ผ๐—ถ๐—ป๐˜ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Calculate the length of a line segment. 2) Find the coordinates of the midpoint of a line segment. ๐Ÿฏ.๐Ÿฑ ๐—˜๐—พ๐˜‚๐—ฎ๐˜๐—ถ๐—ผ๐—ป๐˜€

Maramawit abate ๐Ÿ‡ช๐Ÿ‡นJul 3, 2026

๐Ÿฏ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ ๐—ด๐—ฒ๐—ผ๐—บ๐—ฒ๐˜๐—ฟ๐˜† ๐Ÿฏ.๐Ÿญ ๐—–๐—ผ๐—ผ๐—ฟ๐—ฑ๐—ถ๐—ป๐—ฎ๐˜๐—ฒ๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Use and interpret Cartesian coordinates in two dimensions. ๐Ÿฏ.๐Ÿฎ ๐——๐—ฟ๐—ฎ๐˜„๐—ถ๐—ป๐—ด ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ Draw straight-line graphs for Examples include: linear equations. โ€ข y = โ€“2x + 5 โ€ข y = 7 โ€“ 4x โ€ข 3x + 2y = 5 ๐Ÿฏ.๐Ÿฏ ๐—š๐—ฟ๐—ฎ๐—ฑ๐—ถ๐—ฒ๐—ป๐˜ ๐—ผ๐—ณ ๐—น๐—ถ๐—ป๐—ฒ๐—ฎ๐—ฟ ๐—ด๐—ฟ๐—ฎ๐—ฝ๐—ต๐˜€ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Find the gradient of a straight line. 2) Calculate the gradient of a straight line from the coordinates of two points on it. ๐Ÿฏ.๐Ÿฐ ๐—Ÿ๐—ฒ๐—ป๐—ด๐˜๐—ต ๐—ฎ๐—ป๐—ฑ ๐—บ๐—ถ๐—ฑ๐—ฝ๐—ผ๐—ถ๐—ป๐˜ ๐—ก๐—ผ๐˜๐—ฒ๐˜€ ๐—ฎ๐—ป๐—ฑ ๐—ฒ๐˜…๐—ฎ๐—บ๐—ฝ๐—น๐—ฒ๐˜€ 1) Calculate the length of a line segment. 2) Find the coordinates of the midpoint of a line segment. ๐Ÿฏ.๐Ÿฑ ๐—˜๐—พ๐˜‚๐—ฎ๐˜๐—ถ๐—ผ๐—ป๐˜€